The service-time distribution describes the probability P that the service time of the customer will be no more than t hours. If m is the mean number of customers serviced in an hour, then p = 1 - e^{-mt}. Suppose a computer technical support representative can answer calls from 6 customers in an hour. What is the probability that a customer will be on hold less than 30 minutes? a. 65% c. 85% b. 75% d. 95%
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We are given that the representative can answer calls from 6 customers in an hour. So, m = 6. Show more…
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The service-time distribution describes the probability P that the service time of the customer will be no more than t hours. If m is the mean number of customers serviced in an hour, then p = 1 - e^-mt. Suppose a computer technical support representative can answer calls from 6 customers in an hour. What is the probability that a customer will be on hold less than 30 minutes? a. 65% b. 75% c. 85% d. 95%
Danielle F.
The mean and standard deviation of service times for customers at a post office are known to be 2.93 minutes and 1.79 minutes, respectively. (a) Can you calculate the probability that the average service time for the next two customers is less than 2.7 minutes? If so, calculate the probability. If not, explain why not. (b) What is the approximate probability that the total service time for the next 65 customers exceeds three hours? (Assume that the next 65 customers represent a simple random sample and that there is always a customer waiting in line.)
Stanley E.
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